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Balancing Binary Search Trees

We can make the search, insert, and remove operations to work in time \( \Oh{\Lg n} \), where \( n \) is the number of the keys in the tree, by balancing the trees. Balancing ensures that the height of the BST is \( \Oh{\Lg n} \). Many variants of balanced BSTs have been proposed, see, for instance, this wikipedia link. In the following sections, we’ll see

  • ​ AVL trees, which were the first balanced BSTs, and

  • ​ red-black trees, which are commonly used in many standard libraries.

However, we first show the key technique used in balancing both of these BST classes: rotations.

Rotations

A common operation used when balancing BSTs is rotation.

  • ​ In left rotation of a node \( x \) with a right child \( y \), we transform the sub-tree rooted at \( x \) so that

    • ​ \( y \) becomes the root of the sub-tree,

    • ​ \( x \) becomes the left child of \( y \), and

    • ​ the left child of \( y \) becomes the right child of \( x \).

  • ​ The right rotation is the dual operation for a node with a left child.

The figure below shows the rotattions graphically. The shaded triangles denote sub-trees and can be empty.

_images/bst-rotate.png

A key fact is that the left and right rotations preserve the BST property: If the BST property holds before a rotation, then it holds after the rotation. We can see this from the figure above for left rotation as follows:

  • ​ Traversing the nodes in the subtree in inorder before the left rotation gives the keys in subtree 1, that of \( x \), those in subtree 2, that of \( y \) and those in subtree 3.

  • ​ Traversing the nodes in the subtree in inorder after the left rotation gives the keys in subtree 1, that of \( x \), those in subtree 2, that of \( y \) and those in subtree 3.

A similar analysis can be performed for the right rotation.